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Beam Reinforcement Detailing Ld, 2d Zones, Stirrup Spacing & Lap Locations

Beam Reinforcement Detailing as per IS 13920 | Ld, 2d Zones, Stirrup Spacing & Lap Locations

🔩 Beam Reinforcement Detailing
As per IS 456 & IS 13920

2d Plastic Hinge Zones | Stirrup Spacing S1 & S2 | Development Length Ld | Laps in Top & Bottom Bars
✍️ Published by Er. Kuljit Singh 📅 April 3, 2026 | Arshavtar.in

In reinforced concrete design, proper beam detailing ensures ductile behavior, especially in seismic zones. This guide explains stirrup spacing, effective depth ‘d’, 2d plastic hinge length, development length Ld, and lap locations for top and bottom reinforcement. We use a practical example: beam clear span = 5.5 m (face to face of columns), both side column cover 40 mm, interconnected beam at mid-span (width 400 mm), stirrups S1 = 100 mm (near supports & central beam) and S2 = 125/150 mm in mid regions.

📌 Key Reference: IS 456:2000 (Plain & Reinforced Concrete) and IS 13920:2016 (Ductile Detailing for Earthquake Resistant Structures). The spacing “2d” is the backbone of seismic detailing.

📐 1. Understanding Effective Depth ‘d’ & Clear Span

Effective depth (d) is the distance from extreme compression fiber (top) to centroid of tension reinforcement. It is NOT the span length! For a typical beam of total depth 500 mm, clear cover 25 mm, 8mm stirrup & 16mm bar: d ≈ 500 – 25 – 8 – 8 = 459 mm. In our worked example, we take d = 450 mm for calculations.

Clear span (face to face of columns) = 5300 mm (5.5 m minus covers). The 2d value = 2 × 450 = 900 mm – this is the mandatory plastic hinge zone length from each column face.

📏 2. Stirrup Spacing: S1=100mm & S2=125/150mm – Where & Why?

As per IS 13920 Cl. 6.3.5, within a distance of 2d from column face (plastic hinge region), maximum spacing shall be minimum of (d/4, 8×φlong, 135 mm). With d=450 mm, d/4=112.5 mm → S1=100 mm is compliant. In mid-span (outside 2d), spacing ≤ d/2 = 225 mm, so S2=125 or 150 mm works fine.

Left end 2d zone Right end 2d zone Central 2d zone (both sides of mid beam) S1=100mm S1=100mm S2 spacing S2 spacing Column Column ⚫ Connecting beam at center
Fig 1: Plastic hinge zones (2d) at ends and around central connecting beam – S1=100mm everywhere in red/yellow zones.

🧱 3. Length Calculation for 5300 mm Clear Span (No Mid Load vs With Mid Beam)

Case2d length (each side, mm)Length available for S2 spacing (mid zone)
Without central beam900 mm (both ends)5300 – 2×900 = 3500 mm
With central connecting beam (our case)900 mm ends + 900 mm each side of center beam5300 – (4×900) = 1700 mm (split into two parts ~850 mm each)

Billing quantity: For one beam (with central beam), total stirrups = 2 end zones (22 nos) + central zone 1800mm/100 = 18 stirrups + mid zones (≈1700/125 ≈14 stirrups) → ~54 stirrups per beam.

📌 4. Development Length (Ld) at End Supports & Bottom Mid‑support

Development length Ld is the minimum length of bar required to transfer stress to concrete. As per IS 456 Cl. 26.2.1, Ld = (φ × σs) / (4 × τbd). For Fe500 & M25 concrete, Ld for 16mm bar ≈ 47φ = 752 mm.

  • At end supports (columns): Bottom bars must extend beyond the column face by at least Ld or 12φ (whichever greater) into the support. Additionally, tension bars should be anchored properly with standard hook if space is limited.
  • Mid‑span bottom support (central column/beam junction): For a continuous beam over a central column, bottom bars at the intermediate support require development length on both sides into the span. As per IS 13920, at least 1/3 of bottom bars should be continuous through the joint, and others anchored beyond the face with Ld.

🧮 5. Practical Bar Calculations: End Support & Center Support (Top Reinforcement)

📌 End Support (Column face) – Bottom bars requirement

Assume factored moment at end support = 120 kNm (typical). Using Fe500, M25, required Ast ≈ 850 mm². Provide 4-16mm dia bars (Ast = 804 mm²) at bottom. Development length check: For 16mm bar, Ld = 752 mm. Column width = 400 mm → straight embedment not sufficient. Provide 90° hook (8φ bend) + straight length. Total anchorage = straight embedment (400 – cover) + 8×16 = 400-40 + 128 = 488 mm < 752 mm → still insufficient → increase to 135° hook or provide mechanical anchorage. Alternatively, use larger column or bend bars with L-shaped hook (10φ bend) as per IS 456.

Minimum bottom bars at end support: 2 bars (≥12mm dia) must be extended into support by Ld. In practice, extend all bottom bars into column with standard hook.

🏗️ Center Support (Middle Column) – Top reinforcement (negative moment)

Over central column, hogging moment is high. For a continuous beam with central load, required top steel Ast ≈ 1100 mm². Provide 5-16mm bars (1005 mm²) or 4-20mm (1256 mm²). Detailing rules (IS 13920):

  • At least 1/4 of the top bars shall be continuous throughout the length of the beam (typically 2 nos of 16mm).
  • Remaining top bars shall extend beyond the face of central column by at least Ld (752 mm) or 12φ, whichever greater, and also at least d/3 (150 mm) beyond the point of inflection.
  • All top bars at central support must be anchored with development length on both sides of the column. Since column width = 400 mm, provide 135° hooks or bends to achieve total Ld.
  • Spacing between top bars: should not exceed 200 mm in plastic hinge zone.

Curtailment example: For 5.3m clear span, extend 50% of top bars (alternate bars) up to Ld/3 from column face? Actually as per IS 13920, top bars must extend at least 0.3 × clear span (1590 mm) from column face for seismic resistance. Always follow structural drawings.

📐 Bottom bars at central support – continuity requirement

As per IS 13920 Cl. 6.2.3, at least 1/3 of bottom reinforcement shall be continuous through the joint (for seismic resistance). For our beam with 4 bottom bars (16mm), provide 2 bars (min 2 nos) continuous across central column. The remaining bottom bars shall be terminated beyond the column face with Ld and 135° hooks. This ensures ductile behavior under load reversal.

🔄 6. Lap Locations for Top Bars & Bottom Bars (Critical for safety)

Lap splices should be placed in regions of low stress and away from plastic hinges. IS 13920 strictly prohibits laps within the 2d zone (plastic hinge region).

📍 Top Bars (Negative reinforcement)

Top bars resist hogging moment over supports. Lap splices for top bars should be located in the mid‑span zone (flexural tension zone for top steel is not critical) or preferably at locations where moment is minimum. Never lap top bars within 2d from column face. As per code, if lap is unavoidable, provide additional stirrups and ensure lap length 1.3Ld for compression (top bars often in compression over support but may be tension under seismic reversal – so best to lap at mid-span where moments are low).

📍 Bottom Bars (Positive reinforcement)

Bottom bars lap splices should be placed near the mid-span or within the central half but not in the 2d plastic hinge zones (ends). For the central column support, bottom bars are continuous or lapped over the column with extra stirrups. At the mid-span, lap splices for bottom bars should be staggered and located only in zones where the moment envelope is low – typically at points of inflection (if known).

❌ NO lap in 2d ❌ NO lap in 2d ❌ NO lap central 2d ✅ Top bar lap allowed here (mid-span) ✅ Bottom bar lap allowed near mid (avoid supports) 💡 Top bar lap: within central half, staggered >1.3 Ld 💡 Bottom bar lap: away from supports, preferably at mid-span region
Fig 2: Zones where lap splices are prohibited (red hatched) – avoid 2d zones at ends and around central column.

📊 7. Development Length (Ld) Quick Reference Table

Bar Dia (mm)Fe415 (M25) Ld (mm)Fe500 (M25) Ld (mm)Remarks
12564564* (≈47φ=564)Bottom bars at supports must embed ≥ Ld
16752752Provide standard hook if column width less
20940940End anchors mandatory

For a column width of 400 mm, Ld for 16mm bar (752 mm) cannot be achieved straight; provide 90° hook (8φ bend) or mechanical anchorage as per IS 456.

🏗️ 8. Detailing at Center Support (Middle Column with Connecting Beam)

When a connecting beam frames into the main beam at mid-span, it transfers concentrated load. The main beam must be detailed as follows:

  • Stirrups: Provide S1=100 mm spacing for length 2d on both sides of the center beam (plastic hinge zone).
  • Bottom bars: At least 1/3 of bottom reinforcement shall be continuous through the joint; remaining bars terminated beyond the column face with Ld and 135° hooks.
  • Top bars: Continuous over the central support (if monolithic) and developed beyond the column face by at least Ld.
  • Lap splices: Avoid splicing any bar within 2d from the central column face. All laps shall be placed in the adjacent S2 zones.
Pro tip for billing & site execution: The 2d zones (plastic hinge) demand closed stirrups with 135° hooks, spacing not exceeding 100mm (or d/4). Always ensure first stirrup at ≤50mm from column face.

📐 9. Worked Example – Summary for Span 5300 mm (d=450 mm)

Clear span (face to face) = 5300 mm
Effective depth d = 450 mm → 2d = 900 mm
🔹 End plastic hinge zones (each side): 900 mm, S1 = 100 mm
🔹 Central zone (due to connecting beam): 900 mm left + 900 mm right = 1800 mm, S1 = 100 mm
🔹 Remaining length for S2 (150 mm spacing) = 5300 – 3600 = 1700 mm → placed in two segments of ~850 mm each
📌 Total stirrups ≈ (2× (900/100+1) ) + (1800/100 -1) + (1700/150 -1) = 22 + 17 + 11 = 50 to 54 Nos (depends on exact rounding).
💡 Bottom development length Ld (16mm Fe500) = 752 mm → extend into column with hook.

❓ Frequently Asked Questions (FAQ)

What is the meaning of 2d in beam detailing?
‘2d’ means two times the effective depth of the beam. It defines the plastic hinge region where stirrups must be closely spaced (S1) to provide ductility under earthquake loads. For d=450 mm, 2d=900 mm from column face.
Why can’t we provide lap splices inside 2d zone?
IS 13920 prohibits laps in plastic hinge regions because laps reduce ductility and may cause premature failure during stress reversals. Laps should be located in zones of lower moment (mid-span).
How do I calculate development length Ld for bottom bars at end support?
Ld = (φ × 0.87fy) / (4 × τbd). For Fe500, M25, τbd = 1.4 N/mm², Ld ≈ 47φ. For 16mm bar → 752 mm. If column width is less, use standard hook (8φ bend) or increase grade of concrete.
What is the minimum top reinforcement over a central support?
At least 1/4 of the top bars (or minimum 2 bars) must be continuous throughout the beam length. Remaining bars extend at least Ld beyond column face. Also, total top steel should be capable of resisting negative moment.
How does a central connecting beam affect stirrup spacing?
The central beam introduces a concentrated load, creating a plastic hinge region on both sides of the junction. Hence 2d zones (S1=100mm) are required at ends and around central beam, reducing mid-span S2 length.
Can I use S2=150 mm spacing in all mid-span if no central beam?
Yes, outside the 2d end zones, maximum spacing allowed is d/2 (225mm for d=450mm). So 150mm is acceptable. However, check minimum shear reinforcement requirement as per IS 456.

🚧 For any clarification, contact Er. Kuljit Singh via Arshavtar.in | This article is for educational purpose. Always follow approved structural drawings.

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